Lesson 3.4 Solving Complex 1-variable Equations !exclusive!

( x \neq 2 ) Step 2: Multiply both sides by ( x-2 ) ( 3 + (x-2) = 7 ) ( x + 1 = 7 ) → ( x = 6 ) (valid, since ( 6 \neq 2 ))

Example: ( 2(x+3) = 2x + 6 ) → ( 2x+6 = 2x+6 ) → True for all ( x ). Solution: All real numbers. lesson 3.4 solving complex 1-variable equations

The crowd gasped. Kael smiled. He whispered the Four Steps: ( x \neq 2 ) Step 2: Multiply

( \sqrt2(4)+1 - 3 = \sqrt9 - 3 = 3-3=0 ) ✔ works. lesson 3.4 solving complex 1-variable equations

( 3 = 7 ) → Contradiction!

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